Физика Срочно !пожаулйста!Во сколько раз уменьшилось давление азота в сосуде, если при неизменной
температуре и кол-ве вещества объем увеличить в 2 раза. Срочно!Ответы на вопрос
Ответ:
Объяснение:
По уравнению Менделеева Клаперерона если объем увеличить в 2 раза то давление уменьшится в 2 раза
Pressure Change in a Vessel with Increased Volume
When the volume of a vessel containing a gas is increased while keeping the temperature and amount of substance constant, the pressure of the gas decreases. This relationship is described by Boyle's Law, which states that the pressure of a given amount of gas is inversely proportional to its volume at constant temperature.
Boyle's Law: Boyle's Law can be expressed as: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.
To calculate the change in pressure when the volume is increased by a certain factor, we can use the formula:
P2 = P1 * (V1 / V2)
Where: - P1 = initial pressure - V1 = initial volume - V2 = final volume - P2 = final pressure
Given that the volume is increased by 2 times, we can use this formula to calculate the change in pressure.
Calculation
Using the formula P2 = P1 * (V1 / V2), and assuming the initial pressure is P1 and the initial volume is V1, and the final volume is 2 times the initial volume (2 * V1), we can calculate the final pressure P2.
Let's assume the initial pressure P1 = 1 atm and the initial volume V1 = 1 unit.
P2 = 1 atm * (1 unit / 2 units) P2 = 1 atm * 0.5 P2 = 0.5 atm
So, the final pressure P2 is 0.5 times the initial pressure P1.
Conclusion
Therefore, when the volume of a vessel containing a gas is increased by 2 times, the pressure of the gas decreases to half of its initial value.
This conclusion is based on the application of Boyle's Law, which states that the pressure of a given amount of gas is inversely proportional to its volume at constant temperature.
I hope this helps! If you have further questions or need additional assistance, feel free to ask.
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