Question

Изменение магнитного потока через проводящий замкнут.контур составило 0,5 Вб за 50 мс. Чему равна по модулю ЭДС в контуре.

Answer 1

Ответ:

Объяснение:

| ЭДС ) = ΔФ / Δt = 0,5 / (50·10⁻³) = 10 В

Answer 2

Дано:

ΔФ = 0,5 Вб

Δt = 50 мс = 5×10⁻² с

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Найти:

ε - ?

Решение:

Для нахождения по модулю ЭДС в контуре, определяется вот такая формула, именно по такой формуле мы найдем ЭДС в контуре:

ε = ΔФ/Δt - ЭДС в контуре

ε = 0,5 Вб / 5×10⁻² с = 10 В

Ответ: ε = 10 В

Answer 3

Calculating the Electromotive Force (EMF) in the Circuit

To calculate the electromotive force (EMF) in the circuit, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force in any closed circuit is equal to the rate of change of the magnetic flux through the circuit.

Given: - Change in magnetic flux through the conducting closed circuit: 0.5 Wb - Time taken for the change: 50 ms

Using Faraday's law, the formula to calculate the induced EMF in the circuit is:

EMF = -dΦ/dt

Where: - EMF is the electromotive force - dΦ/dt is the rate of change of magnetic flux

Calculation

Substitute the given values into the formula: EMF = -dΦ/dt = -ΔΦ/Δt

Given: - Change in magnetic flux (ΔΦ): 0.5 Wb - Time taken for the change (Δt): 50 ms

Converting the time to seconds: Δt = 50 ms = 50 × 10^-3 s = 0.05 s

Now, calculate the EMF: EMF = -ΔΦ/Δt = -0.5 Wb / 0.05 s = -10 V

So, the magnitude of the electromotive force (EMF) in the circuit is 10 V.