Question

В процессе работы тепловой машины за некоторое время рабочим телом было получено от нагревателя количество теплоты 2,1 МДж, передано холодильнику 1 МДж. Определи КПД тепловой машины. Ответ (округли до целого числа): ​

Answer 1

Дано: QH=2,1*10^6 Дж

QX=1*10^6 Дж

Найти:η

η=(Qн-Qx)/Qн

η=(2,1*10^6-1*10^6)/(2,1*10^6)≈0,5

Ответ: КПД тепловой машины составляет 50%

Answer 2

Calculation of Efficiency of a Heat Engine

To determine the efficiency of a heat engine, we need to calculate the ratio of the useful work output to the heat input. In this case, the heat input is the amount of heat received from the heater, and the useful work output is the amount of heat transferred to the refrigerator.

Given: - Heat received from the heater: 2.1 MJ - Heat transferred to the refrigerator: 1 MJ

To calculate the efficiency, we can use the formula:

Efficiency = (Useful work output) / (Heat input)

In this case, the useful work output is the heat transferred to the refrigerator, and the heat input is the heat received from the heater.

Plugging in the values:

Efficiency = (1 MJ) / (2.1 MJ)

Calculating the efficiency:

Efficiency = 0.476 (rounded to the nearest whole number)

Therefore, the efficiency of the heat engine is approximately 48%.