Question

атом якому прискорювач надав швидкість 0,6 с випустив фото у напрямку свого руху якою є швидкість руху протона відносно прискорювача? ​

Answer 1

Ответ:На фото решено

Объяснение:

Answer 2

Speed of Proton Relative to Accelerator

The speed of a proton relative to an accelerator can be calculated using the given information. Let's break it down step by step.

Given: - Acceleration provided by the accelerator: 0.6 c (where c is the speed of light) - Direction of the proton's motion: in the direction of the released photo

To find the speed of the proton relative to the accelerator, we can use the relativistic velocity addition formula.

The formula for adding velocities in special relativity is: \[ v = \frac{u + v}{1 + \frac{uv}{c^2}} \] Where: - \( v \) = relative velocity of the proton with respect to the accelerator - \( u \) = velocity of the accelerator - \( v \) = velocity of the proton - \( c \) = speed of light

Given: - \( u = 0.6c \) (acceleration provided by the accelerator) - \( v = c \) (speed of light, as the speed of light is constant)

Plugging these values into the formula, we get: \[ v = \frac{0.6c + c}{1 + \frac{0.6c \cdot c}{c^2}} \] \[ v = \frac{1.6c}{1 + 0.6} \] \[ v = \frac{1.6c}{1.6} \] \[ v = c \]

Therefore, the speed of the proton relative to the accelerator is the speed of light (c).

This means that the proton is moving at the speed of light relative to the accelerator, in the direction of the released photo.