Question

На ліве плече важеля, довжиною 20 см, підвісили вантаж 500 г. Вантаж якої маси необхідно підвісити на праве плече важеля, довжиною 1м, щоб важіль перебував у рівновазі. Знайти вагу кожного вантажу та силу тяжіння яка діє на кожен вантаж та на важіль. Масою важеля знехтувати. СРОЧНО!!

Answer 1

Ответ:

1) 500:20=25

2) 100000+25=100025

відповідь: 100025

Answer 2

Problem Analysis

We are given a lever with a length of 20 cm and a weight of 500 g hanging from the left side. We need to find the weight of the load that should be hung from the right side of the lever, which has a length of 1 m, in order to keep the lever in equilibrium. We also need to determine the weight of each load and the force of gravity acting on each load and the lever.

Solution

To solve this problem, we can use the principle of moments, which states that for an object to be in equilibrium, the sum of the clockwise moments must be equal to the sum of the counterclockwise moments.

Let's denote the weight of the load on the left side of the lever as W1 and the weight of the load on the right side as W2. We can set up the following equation based on the principle of moments:

Clockwise moments = Counterclockwise moments

The clockwise moment is given by the product of the weight and the distance from the pivot point (fulcrum). The counterclockwise moment is given by the product of the weight and the distance from the pivot point.

For the left side of the lever: W1 * 20 cm = 500 g * 9.8 m/s^2 * 0.2 m [[1]]

For the right side of the lever: W2 * 1 m = W1 * 20 cm [[2]]

We can solve equation [[2]] for W2: W2 = (W1 * 20 cm) / 1 m [[3]]

Now, let's substitute the value of W1 from equation [[1]] into equation [[3]] to find W2: W2 = ((500 g * 9.8 m/s^2 * 0.2 m) * 20 cm) / 1 m

Simplifying the equation: W2 = 500 g * 9.8 m/s^2 * 0.2 m * 20 cm / 1 m

Converting the units: W2 = 500 g * 9.8 m/s^2 * 0.2 m * 0.2 m / 1 m

Calculating the value: W2 = 196 N

Therefore, the weight of the load that needs to be hung from the right side of the lever is 196 N.

To find the weight of each load, we can use the equation: Weight = mass * acceleration due to gravity

For the left side of the lever: Weight1 = 500 g * 9.8 m/s^2

For the right side of the lever: Weight2 = 196 N

Therefore, the weight of the load on the left side of the lever is 4.9 N (500 g * 9.8 m/s^2), and the weight of the load on the right side of the lever is 196 N.

The force of gravity acting on each load and the lever is equal to their respective weights.

Summary

- The weight of the load that needs to be hung from the right side of the lever is 196 N. - The weight of the load on the left side of the lever is 4.9 N. - The weight of the load on the right side of the lever is 196 N. - The force of gravity acting on each load and the lever is equal to their respective weights.

Please note that the above calculations assume ideal conditions and neglect any other forces or factors that may affect the system.