Question

механизм, КПД которого 80% а мощность P=40 кВт, работает в течение промежутка времени t=10с определите полезную работу которую он выполняет​

Answer 1

надеюсь здесь всё понятно

Answer 2

Calculation of Useful Work

To calculate the useful work performed by a mechanism with an efficiency (η) of 80% and a power (P) of 40 kW over a time interval (t) of 10 seconds, we can use the formula:

Useful Work (W) = Efficiency (η) × Power (P) × Time (t)

Substituting the given values:

W = 0.8 × 40 kW × 10 s

Calculating the result:

W = 320 kJ

Therefore, the mechanism performs 320 kJ of useful work over the given time interval.