Question

Задача з фізики. 100б. (подивіться на фото). Знайти S34-? При гальмуванні від швидкості 40 км/год до повно 22 зупинки автомобіль пройшов шлях 16 м. Який шлях проїде гей автомобіль по тій самій дорозі при зменшенні швидкості від 100 км/год до 60 км/год ? Вважайте, що прискорення при гальмуваннi постійне А однакове в обох випадках.

Answer 1

Відповідь: 64 м

Пояснення:

Answer 2

Problem Analysis

To solve this physics problem, we need to find the distance traveled by the car when its speed decreases from 100 km/h to 60 km/h. We are given that the car traveled a distance of 16 m when its speed decreased from 40 km/h to 22 km/h. We are also told that the deceleration is constant in both cases.

Solution

Let's denote the initial speed of the car as v1 and the final speed as v2. We are given that v1 = 100 km/h and v2 = 60 km/h. We are also given that the car traveled a distance of 16 m when its speed decreased from 40 km/h to 22 km/h.

To find the distance traveled by the car when its speed decreases from 100 km/h to 60 km/h, we can use the concept of uniform acceleration. The formula to calculate the distance traveled during uniform acceleration is:

S = (v1^2 - v2^2) / (2a)

where S is the distance traveled, v1 is the initial velocity, v2 is the final velocity, and a is the acceleration.

In this case, the acceleration is negative because the car is decelerating. Let's denote the acceleration as a.

Using the given information, we can set up the following equation:

16 = (40^2 - 22^2) / (2a)

Simplifying the equation, we get:

16 = (1600 - 484) / (2a)

16 = 1116 / (2a)

Cross-multiplying, we get:

16 * 2a = 1116

32a = 1116

Solving for a, we get:

a = 1116 / 32

a ≈ 34.875 m/s^2

Now that we have the value of a, we can use it to find the distance traveled when the speed decreases from 100 km/h to 60 km/h. Let's denote this distance as S34.

Using the formula mentioned earlier, we have:

S34 = (100^2 - 60^2) / (2a)

Substituting the value of a, we get:

S34 = (10000 - 3600) / (2 * 34.875)

Simplifying the equation, we get:

S34 = 6400 / 69.75

S34 ≈ 91.7 m

Therefore, the car will travel approximately 91.7 meters when its speed decreases from 100 km/h to 60 km/h on the same road.

Answer

The car will travel approximately 91.7 meters when its speed decreases from 100 km/h to 60 km/h on the same road, assuming the deceleration is constant and equal to the value calculated earlier.