Question

758. Набирая воду из колодца в деревне, человек уронил пустое ведро в колодец с постамента. Высота постамента 1 м, глу- бина колодца 5 м. Определите скорость падающего ведра в момент удара о поверхность воды.​ Помогите пожалуйста срочно!!!!Даю 30 баллов

Answer 1

Ответ: 10,95м/с

Объяснение:

Дано:

h=1м

h2=5м

g=10Н/кг

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V-?

V=√(2gh)=√(2g(h1+h2))=√(2*10*(1+5))=10,95м/с

Answer 2

To determine the speed of the falling bucket at the moment it hits the surface of the water, we can use the principles of physics. Specifically, we can apply the laws of motion and the conservation of energy.

Given Information:

- Height of the pedestal: 1 m - Depth of the well: 5 m

Approach:

1. First, we need to find the time it takes for the bucket to fall from the top of the pedestal to the surface of the water. 2. Then, we can calculate the speed of the falling bucket using the time and the height of the pedestal.

Calculation:

1. To find the time of fall, we can use the equation for the time it takes for an object to fall freely under gravity:

t = sqrt(2h/g)

Where: - t is the time of fall - h is the height of the pedestal (1 m) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Plugging in the values, we get:

t = sqrt(2 * 1 / 9.8) ≈ 0.45 s

Therefore, it takes approximately 0.45 seconds for the bucket to fall from the top of the pedestal to the surface of the water.

2. Now, we can calculate the speed of the falling bucket using the formula:

v = g * t

Where: - v is the speed of the falling bucket - g is the acceleration due to gravity (approximately 9.8 m/s^2) - t is the time of fall (0.45 s)

Plugging in the values, we get:

v = 9.8 * 0.45 ≈ 4.41 m/s

Therefore, the speed of the falling bucket at the moment it hits the surface of the water is approximately 4.41 m/s.

Please note that this calculation assumes ideal conditions, neglecting factors such as air resistance and the buoyancy of the bucket in water.