Question

Домашнее задание Задачи для самостоятельного решения. No1. Мальчик массой 45 КГ прыгнул на берег со скоростью 1,5 м/с с неподвижной лодки массой 1,2 т. Какую скорость приобрела лодка? Архів​

Answer 1

Ответ:

67.5 : 1000 = 0,0675 м. с. - скорость плота. Тут уже более легкое тело у мальчика а по этому скорость которую он может придать плоту будет очень мала .

Answer 2

Problem Statement

A boy with a mass of 45 kg jumps from a stationary boat with a speed of 1.5 m/s. The boat has a mass of 1.2 tons. What is the velocity acquired by the boat?

Solution

To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

Where: - p is the momentum - m is the mass of the object - v is the velocity of the object

Before the jump, the total momentum is zero because both the boy and the boat are stationary. After the jump, the total momentum should still be zero.

Let's denote the velocity acquired by the boat as V. The momentum of the boy before the jump is given by:

momentum of the boy before = mass of the boy * initial velocity of the boy

momentum of the boy before = 45 kg * 1.5 m/s

The momentum of the boat after the jump is given by:

momentum of the boat after = mass of the boat * velocity of the boat

momentum of the boat after = 1.2 tons * V

Since the total momentum before and after the jump should be equal, we can set up the following equation:

momentum of the boy before = momentum of the boat after

45 kg * 1.5 m/s = 1.2 tons * V

Now, let's solve for V:

V = (45 kg * 1.5 m/s) / (1.2 tons)

To calculate the velocity acquired by the boat, we need to convert the mass of the boat from tons to kilograms. Since 1 ton is equal to 1000 kilograms, the mass of the boat in kilograms is:

mass of the boat = 1.2 tons * 1000 kg/ton

Now, let's substitute the values and calculate V:

V = (45 kg * 1.5 m/s) / (1.2 tons * 1000 kg/ton)

V = 0.05625 m/s

Therefore, the boat acquires a velocity of 0.05625 m/s.