Question

Электропоезд, отходя от станции в течении 0,5 мин двигался с ускорением 0,8 м/с2. Определите путь пройденный телом и скорость в конце этого пути. Дам 30 баллов​

Answer 1

Ответ:

На фото

Объяснение:

Аслан мамонт это ты аслан из 9Б? И 25 гимназия?

Answer 2

Calculation of Distance and Final Velocity

To determine the distance traveled by the train and its final velocity, we need to use the equations of motion. Given the following information:

- Initial velocity (u) = 0 m/s (since the train starts from rest) - Acceleration (a) = 0.8 m/s^2 - Time (t) = 0.5 minutes = 0.5 * 60 = 30 seconds

We can use the following equations of motion:

1. Distance (s) = ut + (1/2)at^2 2. Final velocity (v) = u + at

Let's calculate the distance and final velocity using these equations.

Using equation 1: Distance (s) = (0 * 30) + (0.5 * 0.8 * (30^2)) Distance (s) = 0 + (0.5 * 0.8 * 900) Distance (s) = 0 + 360 Distance (s) = 360 meters

Using equation 2: Final velocity (v) = 0 + (0.8 * 30) Final velocity (v) = 0 + 24 Final velocity (v) = 24 m/s

Therefore, the train travels a distance of 360 meters and has a final velocity of 24 m/s at the end of this distance.

Please let me know if there is anything else I can help you with!