Question

ЗАЛИШИЛОСЬ ДУЖЕ МАЛО ЧАСУ!!!!!! Один маятник здійснює 2 коливання за 4с, а другий здійснює 12 коливань за 6с. Визначте, у якого маятника більший період коливань? У скільки разів? ДАМ 40 БАЛІВ​

Answer 1

Відповідь:

Пояснення:

t1 = 4c

N1 =2

t2=6 c
N2=12
________

T1 -? ; Т2 -?; Т1/Т2 - ?

T= t/N

T1 = 4/2 = 2 (c)

T2 = 6/12 = 0,5 (c)

T1 > T2

T1/T2 = 2/0,5 = 4р.

Відповідь: у першого маятника період коливань більший в 4 рази.

Answer 2

To determine which pendulum has a longer period of oscillation, we need to calculate the period for each pendulum and compare the results.

The period of a pendulum is the time it takes for one complete oscillation, usually measured in seconds. It can be calculated using the formula:

T = 2π√(L/g)

Where: - T is the period of the pendulum in seconds - L is the length of the pendulum in meters - g is the acceleration due to gravity, approximately 9.8 m/s² on Earth

Let's calculate the periods for both pendulums and compare them.

Pendulum 1:

- Number of oscillations: 2 - Time taken: 4 seconds

To find the period, we divide the total time by the number of oscillations: T1 = 4 seconds / 2 oscillations = 2 seconds

Pendulum 2:

- Number of oscillations: 12 - Time taken: 6 seconds

Similarly, we divide the total time by the number of oscillations to find the period: T2 = 6 seconds / 12 oscillations = 0.5 seconds

Comparing the two periods, we find that the period of Pendulum 1 is 2 seconds and the period of Pendulum 2 is 0.5 seconds.

Therefore, Pendulum 1 has a longer period of oscillation compared to Pendulum 2. The period of Pendulum 1 is 4 times longer than the period of Pendulum 2.

I hope this helps! Let me know if you have any further questions.