Question

СРОЧНОООО, ПОЖАЛУЙСТА ДАЮ 40 БАЛЛОВ!!!!!!!! АВТОМОБИЛЬ ЕДЕТ ПО ЗАКРУГЛЁННОЙ ДОРОГЕ С РАДИУСОМ 125 МЕТРОВ И НАКЛОНЯЕТСЯ К ГОРИЗОНТУ ПОД УГЛОМ 30°. С КАКОЙ СКОРОСТЬЮ ДВИГАЕТСЯ АВТОМОБИЛЬ?

Answer 1

360° это полный круг 30° это часть процентов

примерно 11%

100% - 11% = 89%

125 - 89% = 36

ответ 36 скорость автомобиля

Answer 2

Ответ:

++++++++++++++++++++++++

Answer 3

To calculate the speed at which the car is moving, we can use the formula for centripetal acceleration:

a = v^2 / r

where: - a is the centripetal acceleration - v is the velocity of the car - r is the radius of the circular path

We can rearrange the formula to solve for velocity:

v = sqrt(a * r)

Given that the radius of the circular path is 125 meters and the car is inclined at an angle of 30° to the horizon, we need to find the centripetal acceleration.

To find the centripetal acceleration, we can use the formula:

a = g * sin(θ)

where: - a is the centripetal acceleration - g is the acceleration due to gravity (approximately 9.8 m/s^2) - θ is the angle of inclination

Substituting the values, we have:

a = 9.8 * sin(30°)

Calculating this, we find:

a ≈ 4.9 m/s^2

Now, we can substitute the values of a and r into the formula for velocity:

v = sqrt(4.9 * 125)

Calculating this, we find:

v ≈ 17.68 m/s

Therefore, the car is moving at a speed of approximately 17.68 m/s.