Question

A cyclist travels 2/3 of his way with a velocity of 10 m/s and 1/3 of the way with a velocity of 20 m/s. What is the average velocity of the cyclist duringhis journey?​

Answer 1

Ответ:13,3333333 m/s

Объяснение:V=2V1*V2/V1+V2=2*10m/s*20m/s/10m/s+20m/s=400/30=13,3333333m/s

Or V=V1+V2/2=10+20/2=15m/s

(I am not sure)

Answer 2

To find the average velocity of the cyclist during his journey, we can use the formula:

Average Velocity = Total Distance / Total Time

Let's assume that the total distance traveled by the cyclist is D and the total time taken is T.

The cyclist travels 2/3 of his way with a velocity of 10 m/s. This means he covers 2/3 of the total distance at a speed of 10 m/s. So, the distance covered at this speed is (2/3)D and the time taken is (2/3)T.

Similarly, the cyclist travels 1/3 of the way with a velocity of 20 m/s. This means he covers 1/3 of the total distance at a speed of 20 m/s. So, the distance covered at this speed is (1/3)D and the time taken is (1/3)T.

Now, we can calculate the total distance and total time:

Total Distance = (2/3)D + (1/3)D = D

Total Time = (2/3)T + (1/3)T = T

Therefore, the average velocity of the cyclist during his journey is:

Average Velocity = Total Distance / Total Time = D / T

Since the total distance and total time are equal to D and T respectively, the average velocity of the cyclist is D / T.

Unfortunately, the specific values of D and T are not provided in the question, so we cannot calculate the exact average velocity.