Question

Можете помочь пожалуйста Коэффициент передачи повышающего трансформатора к = 0,5. Напряжение нагрузки, подключенной к цепи вторичной обмотки U2 = 216 В. Сопротивление нагрузки R2 = 10,8 Ом, вторичная обмотка сопротивление r = 0,2 Ом. Напряжение и ток в первичной обмотке, например Определить трансформатор ПК.

Answer 1

Calculation of Voltage and Current in the Primary Winding

To determine the voltage and current in the primary winding of the step-up transformer, we can use the formula for the turns ratio of a transformer:

Turns ratio (K) = N2 / N1

Where: - N2 is the number of turns in the secondary winding - N1 is the number of turns in the primary winding

In this case, the turns ratio (K) is given as 0.5. Since it is a step-up transformer, the number of turns in the secondary winding (N2) is greater than the number of turns in the primary winding (N1).

Let's assume the voltage and current in the primary winding as V1 and I1, respectively.

According to the turns ratio formula, we have:

K = V2 / V1 = N2 / N1

Since K is given as 0.5, we can rewrite the equation as:

0.5 = V2 / V1

We also know that the voltage in the secondary winding (V2) is given as 216 V.

Substituting the values into the equation, we can solve for V1:

0.5 = 216 V / V1

Solving for V1, we find:

V1 = 216 V / 0.5 = 432 V

Therefore, the voltage in the primary winding (V1) is 432 V.

To calculate the current in the primary winding (I1), we can use the formula:

I2 / I1 = N1 / N2

Since the transformer is ideal, the power is conserved, and we can use the equation:

V1 * I1 = V2 * I2

Substituting the values we know:

432 V * I1 = 216 V * I2

We know that the resistance of the secondary winding (R2) is 10.8 Ω and the resistance of the secondary winding (r) is 0.2 Ω.

Using Ohm's Law, we can express I2 in terms of V2 and R2:

I2 = V2 / (R2 + r)

Substituting the values:

I2 = 216 V / (10.8 Ω + 0.2 Ω) = 216 V / 11 Ω = 19.64 A

Now, we can solve for I1:

432 V * I1 = 216 V * 19.64 A

I1 = (216 V * 19.64 A) / 432 V = 9.82 A

Therefore, the current in the primary winding (I1) is 9.82 A.

To summarize: - The voltage in the primary winding (V1) is 432 V. - The current in the primary winding (I1) is 9.82 A.

Please note that these calculations assume an ideal transformer and neglect any losses or other factors that may affect the actual values.