Question

Сколько теплоты нужно, чтобы нагреть 2 кг воды на 1 ℃? Дж Сколько теплоты нужно, чтобы нагреть 1 кг алюминия на 5 ℃? Дж Сколько теплоты нужно, чтобы нагреть 3 кг железа на 2 ℃? Дж Сколько теплоты нужно, чтобы нагреть 0,5 кг спирта на 10 ℃? Дж

Answer 1

Ответ:

Не благодари

P s зачем ты собираешься нагревать спирт?

Answer 2

Ответ:

питома теплота на масу та ділимо на температуру

Answer 3

Calculation of Heat Required

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Let's calculate the heat required for each scenario:

1. To heat 2 kg of water by 1 °C: - m = 2 kg - c = specific heat capacity of water (approximately 4186 J/kg°C) - ΔT = 1 °C

Using the formula, we can calculate: Q = 2 kg * 4186 J/kg°C * 1 °C = 8372 J

Therefore, it would require 8372 joules of heat to raise the temperature of 2 kg of water by 1 °C.

2. To heat 1 kg of aluminum by 5 °C: - m = 1 kg - c = specific heat capacity of aluminum (approximately 900 J/kg°C) - ΔT = 5 °C

Using the formula, we can calculate: Q = 1 kg * 900 J/kg°C * 5 °C = 4500 J

Therefore, it would require 4500 joules of heat to raise the temperature of 1 kg of aluminum by 5 °C.

3. To heat 3 kg of iron by 2 °C: - m = 3 kg - c = specific heat capacity of iron (approximately 450 J/kg°C) - ΔT = 2 °C

Using the formula, we can calculate: Q = 3 kg * 450 J/kg°C * 2 °C = 2700 J

Therefore, it would require 2700 joules of heat to raise the temperature of 3 kg of iron by 2 °C.

4. To heat 0.5 kg of alcohol by 10 °C: - m = 0.5 kg - c = specific heat capacity of alcohol (approximately 2500 J/kg°C) - ΔT = 10 °C

Using the formula, we can calculate: Q = 0.5 kg * 2500 J/kg°C * 10 °C = 12500 J

Therefore, it would require 12500 joules of heat to raise the temperature of 0.5 kg of alcohol by 10 °C.

Please note that the specific heat capacities used in these calculations are approximate values and may vary slightly depending on the specific type and purity of the substances involved.

I hope this helps! Let me know if you have any further questions.