Question

Визначити частоту монохроматичного світла якщо імпульс фотона 6.626*10^-28Н*с . Стала планка 6.626*10^-34Дж/с Швидкість світла 3*10^8 м/с.

Answer 1

Ответ:

Объяснение:

Импульс фотона:

p =  h / λ = h·ν / c

Отсюда:

ν = p·c/h

ν = 6,626·10⁻²⁸·3·10⁸ / (6,626·10⁻³⁴) = 3·10¹⁴ Гц

Answer 2

#### Determining the Frequency of Monochromatic Light To determine the frequency of monochromatic light, we can use the equation that relates the energy of a photon to its frequency. The equation is given by: **E = hf** Where: - E is the energy of the photon - h is the Planck's constant (6.626 × 10^-34 J/s) - f is the frequency of the light Given that the energy of the photon is 6.626 × 10^-28 N·s and the Planck's constant is 6.626 × 10^-34 J/s, we can rearrange the equation to solve for the frequency: **f = E / h** Substituting the values into the equation, we get: **f = (6.626 × 10^-28 N·s) / (6.626 × 10^-34 J/s)** Simplifying the expression, we find: **f = 10^6 Hz** Therefore, the frequency of the monochromatic light is 10^6 Hz. Please note that the above calculation assumes that the energy of the photon is given in Newton-seconds (N·s), which is not a standard unit for energy. The correct unit for energy is Joules (J). If the energy is given in Joules, the frequency would be different.