Question

Даю 30 балів!!!!!! Потужність кишенькового ліхтарика дорівнює 2,6 Вт. Визнач силу струму, яку споживає ліхтарик, якщо джерелом живлення служать 5 батарейки(йок) напругою 1,9 в кожна, якi з'єднанi послідовно.

Answer 1

Ответ:

ответ смотри на фотографии дай пожалуйста корону умоляю

Answer 2

To determine the current consumed by the flashlight, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). In this case, the resistance is not given, but we can calculate it using the power (P) and voltage (V) of the flashlight.

Calculating Resistance:

The power (P) of the flashlight is given as 2.6 Watts, and the voltage (V) is not provided. Therefore, we need to calculate the resistance (R) using the formula: P = V^2 / R.

Let's calculate the resistance (R) of the flashlight: ``` P = V^2 / R 2.6 = V^2 / R ```

Since we don't have the value of V, we cannot calculate the resistance (R) at this point.

Calculating Current:

To find the current (I) consumed by the flashlight, we need to know the voltage (V) across the circuit. In this case, the flashlight is powered by 5 batteries connected in series, with each battery having a voltage of 1.9V.

When batteries are connected in series, the total voltage is the sum of the individual battery voltages. Therefore, the total voltage (V_total) across the circuit can be calculated as follows: ``` V_total = V1 + V2 + V3 + V4 + V5 = 1.9 + 1.9 + 1.9 + 1.9 + 1.9 = 9.5V ```

Now that we have the total voltage (V_total), we can calculate the current (I) using Ohm's Law: I = V / R.

However, since we don't have the resistance (R) of the flashlight, we cannot calculate the current (I) at this point.

In summary, without knowing the resistance (R) of the flashlight, we cannot determine the current (I) consumed by the flashlight when powered by 5 batteries with a voltage of 1.9V each.