Question

Q=sinп/3*t по данному уравнению определить qm-? T-? v-?

Answer 1

В общем виде q=qmsinωt.

Значит qm=1.

ω=π/3=2πν.      1/3=2ν.       1=6ν.           ν=1/6.

Т=1/ν=1/(1/6)=6.

Answer 2

Looks like you've got a trigonometric equation there! The equation is $q = \sin(\frac{\pi}{3} \cdot t)$, where $q$ is the dependent variable (presumably displacement), $t$ is time, and $\pi$ is pi.

Now, to find $q_m$ (amplitude), $T$ (period), and $v$ (angular frequency), you can compare it with the general form of a sinusoidal function:

$q(t) = q_m \cdot \sin(v \cdot t)$

Here, $q_m$ is the amplitude, $T$ is the period, and $v$ is the angular frequency.

Comparing the two equations, you can identify the values:

$q_m = 1$ (since the coefficient of $\sin$ is 1)

$T = \frac{2\pi}{v}$ (period is the reciprocal of angular frequency)

$v = \frac{\pi}{3}$ (from the given equation)

So, $q_m = 1$, $T = \frac{2\pi}{\frac{\pi}{3}} = 6$, and $v = \frac{\pi}{3}$.