Question

Яблоко массой 200г свободно падает с ветки яблониина высоте 2 м на землю.Какой будет кинетическая энергия яблока перед ударом о землю?чему будет равна его скорость перед ударом!срочно нужно решение на 2 вопрос !!!

Answer 1

точно кинетическая просто формула кинетической энергии - mu( в квадрате)\2

а потенциальная-Fh

Answer 2

Calculation of Kinetic Energy and Velocity

To calculate the kinetic energy and velocity of an apple falling from a tree branch, we can use the principles of gravitational potential energy and conservation of mechanical energy.

The formula for gravitational potential energy is given by:

Potential Energy (PE) = mass (m) × acceleration due to gravity (g) × height (h)

In this case, the mass of the apple is 200 grams, which is equivalent to 0.2 kilograms. The acceleration due to gravity is approximately 9.8 m/s², and the height from which the apple falls is 2 meters.

Using these values, we can calculate the potential energy:

PE = 0.2 kg × 9.8 m/s² × 2 m

Now, let's calculate the potential energy:

PE = 0.2 kg × 9.8 m/s² × 2 m = 3.92 Joules

The potential energy of the apple before it falls is 3.92 Joules.

According to the law of conservation of mechanical energy, the potential energy is converted into kinetic energy as the apple falls. The formula for kinetic energy is given by:

Kinetic Energy (KE) = 0.5 × mass (m) × velocity (v)²

To find the velocity of the apple just before it hits the ground, we can rearrange the formula:

v = √(2 × KE / m)

Substituting the known values:

v = √(2 × 3.92 J / 0.2 kg)

Now, let's calculate the velocity:

v = √(19.6 m²/s² / 0.2 kg) ≈ √98 m²/s² ≈ 9.9 m/s

The velocity of the apple just before it hits the ground is approximately 9.9 m/s.

Therefore, the kinetic energy of the apple before it hits the ground is 3.92 Joules, and its velocity is approximately 9.9 m/s.

Please note that these calculations assume no air resistance and idealized conditions.