Question

V0=0 a=0,25 S=200m t=?

Answer 1

Ответ:

40 c

Объяснение:

vo=0   a=0.25 м/с²     s=200 м    t=?

===

s=vo+a*t²/2

t=√(2*s/a)=√(2*200/0.25)=40 c

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Answer 2

Объяснение:

$\frac{ {at}^{2} }{2} = \frac{0.25 {t}^{2} }{2} = 200 \\ \\ {t }^{2} = \frac{200 \times 2}{0.25} = \frac{400}{0.25} = 1600 \\ \\ {t }^{2} = 1600 \\ t = 40$

Answer 3

To find the time it takes for an object to travel a certain distance under constant acceleration, you can use the following equation:

$S = V_0 t + \frac{1}{2} a t^2$

Where:

• $S$ is the distance traveled (200 meters in this case).
• $V_0$ is the initial velocity (0 m/s in this case).
• $a$ is the acceleration (0.25 m/s^2 in this case).
• $t$ is the time we want to find.

Plugging in the values:

$200 = 0 \cdot t + \frac{1}{2} \cdot 0.25 \cdot t^2$

Simplifying the equation:

$200 = 0.125t^2$

Now, we need to solve for $t$. First, divide both sides by 0.125:

$t^2 = \frac{200}{0.125} = 1600$

Next, take the square root of both sides:

$t = \sqrt{1600} = 40$

So, it will take 40 seconds for the object to travel 200 meters with an initial velocity ($V_0$) of 0 m/s and a constant acceleration ($a$) of 0.25 m/s^2.