Question

Скорость2 =10 м\с,скорость1=0 м\с время 15 с.,а-?

Answer 1

A=ΔV/Δt=V2-V1/t2-t1=(10м/с-0м/с)/(15с-0с)=10м/с/15с=0,66 м/с²
Нам дано только 15 секунд(t1=0(от начала отсчета))

Answer 2

А = 10/15 ≈ 0,66 м/с²

Answer 3

To calculate the acceleration (a), we can use the formula:

$a = \frac{\text{change in velocity}}{\text{time}}$

Since we have the initial velocity (v1) and the final velocity (v2), the change in velocity is given by:

$\text{change in velocity} = v2 - v1$

Given that:

• $v1 = 0 \, \text{m/s}$ (initial velocity)
• $v2 = 10 \, \text{m/s}$ (final velocity)
• $\text{time} = 15 \, \text{s}$

Let's calculate the acceleration:

$\text{change in velocity} = 10 \, \text{m/s} - 0 \, \text{m/s} = 10 \, \text{m/s}$

$a = \frac{10 \, \text{m/s}}{15 \, \text{s}} \approx 0.67 \, \text{m/s}^2$

So, the acceleration is approximately $0.67 \, \text{m/s}^2$.