Question

Q1=9*10^-6Кл q2=10^6Кл r=8см k=9*10^9 F-?

Answer 1

$F = k \dfrac{|q_{1}||q_{2}|}{R^{2}} \\ \\ F = 9*10^{9} * \dfrac{9*10^{-6} * 10^{6}}{0.08^{2}} = 1265625 * 10^{7} \ [H]$
Ответ: F = 1265625 × 10⁷ H

Answer 2

To calculate the force (F) between two charges (q1 and q2) separated by a distance (r), we can use Coulomb's law:

$F = \dfrac{k \cdot |q1 \cdot q2|}{r^2}$

Where:

• $k = 9 \times 10^9$ N m²/C² (Coulomb's constant)
• $q1 = 9 \times 10^{-6}$ C (charge of the first particle)
• $q2 = 10^6$ C (charge of the second particle)
• $r = 8$ cm (distance between the two charges)

First, we need to convert the distance (r) from centimeters to meters:

$r = 8 \text{ cm} = 0.08 \text{ m}$

Now, we can plug the values into the formula:

$F = \dfrac{(9 \times 10^9) \cdot |9 \times 10^{-6} \cdot 10^6|}{(0.08)^2}$

Simplify the expression inside the absolute value:

$F = \dfrac{9 \times 10^9 \cdot |9 \times 10^{-6 + 6}|}{0.0064}$

$F = \dfrac{9 \times 10^9 \cdot 9}{0.0064}$

$F = \dfrac{81 \times 10^9}{0.0064}$

Now, divide the numerator by the denominator:

$F = 12.65625 \times 10^{12}$

Finally, we can express the answer in scientific notation:

$F \approx 1.27 \times 10^{13} \text{ N}$

So, the force (F) between the two charges is approximately $1.27 \times 10^{13}$ Newtons.