Question

X=4-3t x0 , v, s за 2с?

Answer 1

x0=4 м V=-3 м/с   x=4-3*2=-2 м S=x-x0=4-(-2)=6 м

Answer 2

To find the values of x (position), v (velocity), and s (displacement) at t = 2 seconds for the equation x = 4 - 3t, we need to perform the following steps:

Step 1: Find x(2) - Position at t = 2 seconds Step 2: Find v(2) - Velocity at t = 2 seconds Step 3: Find s(2) - Displacement at t = 2 seconds

Step 1: Finding x(2) - Position at t = 2 seconds To find x(2), we plug t = 2 into the equation x = 4 - 3t:

x(2) = 4 - 3 * 2 x(2) = 4 - 6 x(2) = -2

So, x at t = 2 seconds is -2.

Step 2: Finding v(2) - Velocity at t = 2 seconds Velocity (v) is the derivative of position (x) with respect to time (t). Therefore, to find v(2), we take the derivative of the equation x = 4 - 3t and then substitute t = 2:

v(t) = d/dt (4 - 3t) v(t) = -3

v(2) = -3

So, the velocity at t = 2 seconds is -3.

Step 3: Finding s(2) - Displacement at t = 2 seconds Displacement (s) is the change in position from some initial time to the desired time. To find s(2), we subtract the initial position (x₀) from the position at t = 2 seconds:

s(2) = x(2) - x₀ s(2) = (-2) - x₀

Since we don't have the value of x₀ (the initial position), we can't determine the exact displacement at t = 2 seconds without that information.

In conclusion, at t = 2 seconds:

• Position (x) is -2 units.
• Velocity (v) is -3 units per second.
• Displacement (s) cannot be determined without knowing the initial position (x₀).