Question

Дано: m=150 г Q=2805 дж t1=15°с Найти: t2

Answer 1

Q = cm(t²-t¹) t²-t¹ = Q/cm t² = Q/cm + t¹ t² = 2805/150c + 15 = 18,7c + 15  Без знания вещества дальнейшее решение невозможно.

Answer 2

To find the final temperature (t2) of a substance given the initial mass (m), energy transferred (Q), and initial temperature (t1), you can use the specific heat formula:

Q = m * c * Δt

where: Q = Energy transferred (in joules) m = Mass of the substance (in grams) c = Specific heat capacity of the substance (in J/g°C) Δt = Change in temperature (in °C) = t2 - t1

Since we need to find t2, we rearrange the equation:

Δt = Q / (m * c) t2 - t1 = Q / (m * c)

Now, we can solve for t2:

t2 = t1 + Q / (m * c)

We need to know the specific heat capacity (c) of the substance to calculate t2. Since you didn't provide the specific heat capacity, I'll assume the substance is water, which has a specific heat capacity of approximately 4.18 J/g°C.

Now, let's plug in the values:

m = 150 g Q = 2805 J t1 = 15°C c = 4.18 J/g°C (specific heat capacity of water)

t2 = 15 + 2805 / (150 * 4.18) t2 = 15 + 2805 / 627 t2 = 15 + 4.47 t2 ≈ 19.47°C

So, the final temperature (t2) of the substance is approximately 19.47°C.