Question

M=10кг S=50м V1=5м/с V2=15м/с F=?

Answer 1

v=v0+at

s=v0t+at^2/2

15=5+at

50=5t+at^2/2

10/t=a

50=5t+(10/t)t^2/2

50=5t+5t=10t

t=5 сек

a=2м/сек

F=m*a= 10*2= 20Н

Answer 2

To find the force (F) involved in this scenario, we can use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (Δp) of an object over time. Mathematically, this can be represented as:

F = Δp / Δt

where Δp is the change in momentum and Δt is the change in time.

The momentum (p) of an object is given by the product of its mass (m) and velocity (v):

p = m * v

Let's calculate the initial momentum (p1) and final momentum (p2) of the object:

Initial momentum (p1) = m * V1 = 10 kg * 5 m/s = 50 kg m/s Final momentum (p2) = m * V2 = 10 kg * 15 m/s = 150 kg m/s

Now, we can calculate the change in momentum (Δp):

Δp = p2 - p1 = 150 kg m/s - 50 kg m/s = 100 kg m/s

Since the time interval (Δt) is not given in the problem, we cannot calculate the exact force (F) involved. The force depends on how much time it takes for the velocity of the object to change from V1 to V2. If we have information about the time interval, we can calculate the force using the formula mentioned earlier.