Question

M=2 т.Q=180Мджt1=20°Ct2=150°CC-?

Answer 1

Q=cm(t2-t1) поэтому c=Q:m(t2-t1) = 180000000Дж:2000кг(150-20)=180000000:260000=692.3 дж|кг*градус

Answer 2

Q=cm(t2-t1)

c=Q/m(t2-t1)

c = 180*10^6 / 2 000 * 130 = 692 (Дж/кг*С)

Answer 3

It seems like you've provided some variables (M, Q, t1, t2) but haven't specified what the equation or problem is. I assume you want to find the value of C. If that's the case, we can use the formula for specific heat:

Q = M * C * ΔT

where: Q = Heat energy transferred (in joules, J) M = Mass of the substance (in kilograms, kg) C = Specific heat capacity of the substance (in J/(kg°C) or J/(kg*K)) ΔT = Change in temperature (in °C or K)

Given: M = 2 kg (kilograms) Q = 180 MJ (megajoules) --> We need to convert this to joules (1 MJ = 1,000,000 J) t1 = 20°C t2 = 150°C

Let's proceed with the calculation:

1. Convert the energy from megajoules to joules: 180 MJ * 1,000,000 J/MJ = 180,000,000 J

2. Calculate the change in temperature (ΔT): ΔT = t2 - t1 = 150°C - 20°C = 130°C

3. Now, rearrange the formula to solve for C: C = Q / (M * ΔT)

Substitute the values: C = 180,000,000 J / (2 kg * 130°C)

Now, we need to convert the temperature from Celsius to Kelvin (since the specific heat capacity is usually given in J/(kg*K)):

130°C + 273.15 K/°C ≈ 403.15 K

C = 180,000,000 J / (2 kg * 403.15 K)

C ≈ 223,579 J/(kg*K)

So, the specific heat capacity of the substance is approximately 223,579 J/(kg*K).