Question

Дано v=3m/c a=1,5m/2 t=6c s-?

Answer 1

Sx=Vxt-axt^2/2=3*6-1.5*36/2=9 m

Answer 2

Sx=Vxt+axt²/2

Sx=3*6+1.5*36/2=45 (м)

Answer 3

To solve for "s," which represents displacement, we can use the formula for uniform acceleration:

s = v*t + (1/2)at^2

where: v = initial velocity t = time a = acceleration

Given the values: v = 3 m/c (I assume "c" means the unit "seconds") a = 1.5 m/2 (I assume you meant 1.5 m/s^2 for acceleration) t = 6 c (again, assuming "c" means seconds)

Let's convert the time to seconds since the unit "c" is unclear:

1 c (century) = 100 years = 100 * 365.25 * 24 * 60 * 60 seconds ≈ 3.15576 x 10^9 seconds

t = 6 c * 3.15576 x 10^9 seconds/c ≈ 1.89345 x 10^10 seconds

Now, we can calculate the displacement "s":

s = 3 m/s * 1.89345 x 10^10 seconds + (1/2) * 1.5 m/s^2 * (1.89345 x 10^10 seconds)^2

First, let's calculate v*t:

v*t = 3 m/s * 1.89345 x 10^10 seconds ≈ 5.68035 x 10^10 meters

Next, let's calculate (1/2)at^2:

(1/2)at^2 = 0.5 * 1.5 m/s^2 * (1.89345 x 10^10 seconds)^2 ≈ 2.54091 x 10^20 meters

Finally, let's add the two results:

s ≈ 5.68035 x 10^10 meters + 2.54091 x 10^20 meters ≈ 2.54091 x 10^20 meters

So, the displacement "s" is approximately 2.54091 x 10^20 meters.