Question

Задание 1. Дано: m=0,6 тонн = 600кг S=3 м² g= 9,8 H/кг ____________ P (давление) =? Задание 2. Дано: P (вещество) = (нефть) 0,8 кг/м³ g= 9,8 H/кг _____________ P (давление) = ? Задание 3. Дано: m= 20кг S= 0,002 м² g= 9,8 H/кг ____________ P (давление) =? Задание 4. Дано: Р (давление) =60кПа Р (вещество) =1000кг/м³ g=9,8H/кг ____________ h=? Задание 5. Дано: Р (вещество)= (ртуть) 13,6 кг/м³ Р (давление)= 27,2 КПа g= 9,8Н/кг ____________ h=? Можете пожалуйста решить?Мне срочно. Я не понимаю как решать (болел). Заранее спасибо.

Answer 1

1.P=F/S=(m*g)/S
F=m*g
2.Вероятно,вы что-то потеряли или же опечатались-формула будет равна P=p*g*h.А глубина не указана.
3.P=F/S=(m*g)/S
F=m*g
4.h=P(давление)/p*g
60 кПа=60 000 Па
5.h=P(давление)/p*g
27,2 кПа=27200 Па

Answer 2

Task 1:

Given: - \( m = 0.6 \) ton = 600 kg - \( S = 3 \) m² - \( g = 9.8 \) m/s²

We need to find the pressure (\( P \)).

To find the pressure (\( P \)), we can use the formula: \[ P = \frac{m \cdot g}{S} \]

Substitute the given values: \[ P = \frac{600 \, \text{kg} \times 9.8 \, \text{m/s}^2}{3 \, \text{m}^2} \]

Calculating: \[ P \approx 1960 \, \text{Pa} \]

Answer: The pressure (\( P \)) is approximately 1960 Pa.

Task 2:

Given: - \( P \) (substance) = (oil) 0.8 kg/m³ - \( g = 9.8 \) m/s²

We need to find the pressure (\( P \)).

The pressure (\( P \)) can be calculated using the formula: \[ P = \text{density} \times g \]

Substitute the given values: \[ P = 0.8 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 \]

Calculating: \[ P \approx 7.84 \, \text{Pa} \]

Answer: The pressure (\( P \)) is approximately 7.84 Pa.

Task 3:

Given: - \( m = 20 \) kg - \( S = 0.002 \) m² - \( g = 9.8 \) m/s²

We need to find the pressure (\( P \)).

Using the formula: \[ P = \frac{m \cdot g}{S} \]

Substitute the given values: \[ P = \frac{20 \, \text{kg} \times 9.8 \, \text{m/s}^2}{0.002 \, \text{m}^2} \]

Calculating: \[ P \approx 98,000 \, \text{Pa} \]

Answer: The pressure (\( P \)) is approximately 98,000 Pa.

Task 4:

Given: - \( P \) (pressure) = 60 kPa - \( \rho \) (substance) = 1000 kg/m³ - \( g = 9.8 \) m/s²

We need to find the height (\( h \)).

The height (\( h \)) can be calculated using the formula: \[ P = \rho \cdot g \cdot h \]

Solving for \( h \): \[ h = \frac{P}{\rho \cdot g} \]

Substitute the given values: \[ h = \frac{60,000 \, \text{Pa}}{1000 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2} \]

Calculating: \[ h \approx 6.12 \, \text{m} \]

Answer: The height (\( h \)) is approximately 6.12 m.

Task 5:

Given: - \( \rho \) (substance) = (mercury) 13.6 kg/m³ - \( P \) (pressure) = 27.2 kPa - \( g = 9.8 \) m/s²

We need to find the height (\( h \)).

The height (\( h \)) can be calculated using the formula: \[ P = \rho \cdot g \cdot h \]

Solving for \( h \): \[ h = \frac{P}{\rho \cdot g} \]

Substitute the given values: \[ h = \frac{27,200 \, \text{Pa}}{13.6 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2} \]

Calculating: \[ h \approx 200 \, \text{m} \]

Answer: The height (\( h \)) is approximately 200 m.