Question

Fупр- 5Н deltaL-5 mm K-?

Answer 1

Fупр = kΔl

k = Fупр/Δl

Δl = 5 мм = 0,005 м

k = 5 Н / 0,005 м = 1000 Н/м

Answer 2

It looks like you've provided some information about a system, but it's not entirely clear what you're asking. Let me try to interpret the provided information:

• Fупр- 5Н: This appears to be the applied force, measured in Newtons (N).
• deltaL-5 mm: This seems to be the change in length, measured in millimeters (mm).

However, I'm not sure what "K" refers to in this context. It could be the spring constant (stiffness) of a material or a coefficient of some kind. Without more context or a specific question, I can't provide a complete answer. Could you please clarify what you're looking for or provide more information about the system you're referring to? That way, I can give you a more accurate response.