Question

M=3,2кг М=0,36 g=9,8 Найти Fтр

Answer 1

Fтр. = uN = umg = 0,36*3,2*9,8 = 11,29 H.

Answer 2

To find Fтр (force of tension), we need to clarify the context of the problem. It seems that M, М, and g represent different quantities with different units, and it's unclear how they are related.

To proceed, I'll assume that M = 3.2 kg, М = 0.36 kg, and g = 9.8 m/s² (acceleration due to gravity on Earth). I'll also assume that you want to find the force of tension (Fтр) in a system involving these masses.

Now, let's consider a scenario where M and М are masses connected by a rope or string passing over a pulley. In this case, we can use Newton's second law of motion to find the force of tension in the rope.

The equation for Newton's second law is:

F = m * a

where: F is the net force acting on an object, m is the mass of the object, and a is the acceleration of the object.

In this scenario, both M and М will have the same acceleration, and we can write the following equations:

For M: Fтр - M * g = M * a ---(1)

For М: М * g - Fтр = М * a ---(2)

We can solve this system of equations to find Fтр. Let's do that:

Substitute the values: M = 3.2 kg М = 0.36 kg g = 9.8 m/s²

Now, let's solve equations (1) and (2):

From equation (1): Fтр - 3.2 kg * 9.8 m/s² = 3.2 kg * a ---(3)

From equation (2): 0.36 kg * 9.8 m/s² - Fтр = 0.36 kg * a ---(4)

Now, we can solve these equations simultaneously to find Fтр:

Adding equations (3) and (4):

Fтр - 3.2 kg * 9.8 m/s² + 0.36 kg * 9.8 m/s² = 3.2 kg * a + 0.36 kg * a Fтр - 31.36 kgm/s² + 3.528 kgm/s² = 3.56 kg * a

Fтр - 27.832 kg*m/s² = 3.56 kg * a

Now, let's find the acceleration (a) of the masses. Since both M and М have the same acceleration (a), we can use either equation (1) or (2) to find it:

From equation (1): Fтр - 3.2 kg * 9.8 m/s² = 3.2 kg * a

a = (Fтр - 3.2 kg * 9.8 m/s²) / 3.2 kg ---(5)

Now, we can substitute the value of a from equation (5) into the equation (6) to solve for Fтр:

Fтр - 27.832 kg*m/s² = 3.56 kg * ((Fтр - 3.2 kg * 9.8 m/s²) / 3.2 kg)

Now, solve for Fтр:

Fтр - 27.832 kg*m/s² = 3.56 kg * (Fтр - 3.2 kg * 9.8 m/s²) / 3.2 kg

Fтр - 27.832 kgm/s² = 3.56 kg * (Fтр - 31.36 kgm/s²) / 3.2 kg

Now, cross-multiply to eliminate the fraction:

3.2 kg * (Fтр - 27.832 kgm/s²) = 3.56 kg * (Fтр - 31.36 kgm/s²)

Now, distribute the terms:

3.2 kg * Fтр - 3.2 kg * 27.832 kgm/s² = 3.56 kg * Fтр - 3.56 kg * 31.36 kgm/s²

Now, isolate Fтр:

3.2 kg * Fтр - 3.56 kg * Fтр = 3.56 kg * 31.36 kgm/s² - 3.2 kg * 27.832 kgm/s²

Combine like terms:

-0.36 kg * Fтр = 112.384 kg*m/s²

Finally, solve for Fтр:

Fтр = 112.384 kg*m/s² / -0.36 kg

Fтр ≈ -312.1778 N

The force of tension (Fтр) is approximately -312.18 Newtons. Note that the negative sign indicates that the force is in the opposite direction to the assumed positive direction. This means that the tension in the rope is acting in the opposite direction.