Question

U=0,4 sin 5 П t Um=? U=? T=?

Answer 1

Відповідь:

Пояснення:

Um = 0,4 B

ω=$\frac{2\pi}{T}$

T= 2π/ω = 2π/5π = 0,4 c

U=0,4 sin 5 П t

Answer 2

It looks like you've provided an equation involving some variables related to a sinusoidal wave. Let's break down the equation and its variables:

Given equation: U = 0.4 * sin(5 * π * t)

In this equation:

• U represents the instantaneous voltage or amplitude of the sinusoidal wave.
• t represents time.

You've asked for values of Um, U, and T. Let's find those:

1. Um: It seems like "Um" might represent the peak amplitude of the sinusoidal wave. The peak amplitude of a sine wave is the maximum positive value that the wave reaches. In this case, the coefficient 0.4 is the amplitude. Therefore, Um = 0.4.

2. U: The equation itself defines the instantaneous voltage at any given time t. Since the equation is U = 0.4 * sin(5 * π * t), there is no separate value for U. The voltage (U) varies with time (t) according to this equation.

3. T: In this equation, there is no explicit period (T) given. The period of a sinusoidal wave is the time it takes to complete one full cycle. The period can be calculated using the formula T = 2π / ω, where ω is the angular frequency. In this case, ω = 5π. So, T = 2π / (5π) = 2/5 seconds.

To summarize:

• Um (peak amplitude): 0.4
• U (instantaneous voltage): U = 0.4 * sin(5 * π * t)
• T (period): 2/5 seconds