
L1=20см; F1=6H; F2=3H; L2=?


Ответы на вопрос

Ответ:
уравнение рычага 6*20=3*х, х=6*20/3= 40см



It seems like you're dealing with a situation related to inductance, where L1 represents the inductance of a coil with 20 cm of length and F1 represents a magnetic field strength of 6 Henrys. You want to find the inductance (L2) of another coil with a magnetic field strength of F2, which is 3 Henrys.
The inductance (L) of a coil is directly proportional to its length (L) and the square of the number of turns (N) in the coil. The formula for inductance is:
L = (μ₀ * N² * A) / l
Where:
- L is the inductance in Henrys (H).
- μ₀ (mu-naught) is the permeability of free space, approximately equal to 4π x 10^(-7) H/m.
- N is the number of turns in the coil.
- A is the cross-sectional area of the coil.
- l is the length of the coil.
We can rearrange the formula to solve for L2:
L2 = (F2 * l2) / (μ₀ * N²)
We have F2 = 3H and F1 = 6H. Since in this problem, we're not given the number of turns (N) or the cross-sectional area (A) of the coils, and we're looking for the inductance of the second coil (L2) with a different length (l2), we can't calculate L2 with the given information.
You would need additional information, such as the number of turns or the cross-sectional area of the coils, to determine the inductance of the second coil (L2) accurately.


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