Question

R1,2,3= 10 Ом U=30 P-?

Answer 1

R = R1 + R2 + R3 = 10 + 10 + 10 = 30 (Ом)

I = U / R

I = 30 / 30

I = 1 A

U1 = I × R1 = 1 × 10 = 10

U2 = I × R2 = 1 × 10 = 10

U3 = I × R3 = 1 × 10 = 10

U = U1 + U2 + U3 = 10 + 10 + 10 = 30

P = U × I = 30 × 1 = 30Вт

P1 = U1 × I = 10 × 1 = 10

P2 = U2 × I = 10 × 1 = 10

P3 = U3 × I = 10 × 1 = 10

P = P1 + P2 + P3 = 10 + 10 + 10 = 30

Answer 2

It seems like you are providing an electric circuit notation. However, the notation is not entirely clear. If you meant R1, R2, and R3 as resistors with values of 10 Ohms each, and U as the voltage across them of 30 volts, then you can find the power (P) dissipated in the resistors using the formula:

$P = \dfrac{U^2}{R}$

Since all resistors have the same value (10 Ohms), the power dissipated in each resistor will be the same. Therefore,

$P = \dfrac{(30)^2}{10} = \dfrac{900}{10} = 90 \text{ Watts}$

So, the power dissipated in each of the resistors R1, R2, and R3 is 90 watts.