Question

V1=6м/сS1=3кмV2=10м/сS2=13кмVср-?​

Answer 1

Ответ:

8,9 v/c

Объяснение:

v1=6 м/с   s1=3000 м    v2=10 м/с    s2=13000 м   vcp=?

===

vcp=(s1+s2)/(t1+t2)

t1=s1/v1=3000/6=500 c

t2=s2/v2=13000/10=1300 c

vcp=(3000+13000)/(500+1300)≈8.9 м/с

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Answer 2

To find the average velocity (Vср) for the entire journey, you can use the formula for average velocity:

$Vср = \frac{ΔS}{Δt}$

Where:

• $ΔS$ is the change in distance.
• $Δt$ is the change in time.

In this case, you're given the initial and final velocities for two segments of the journey and the distances covered in each segment. You need to find the total change in distance and the total change in time for the entire journey.

For the first segment (S1):

• Initial velocity, $V1 = 6 m/s$
• Distance, $S1 = 3 km$

You need to convert the distance from kilometers to meters because the velocity is given in m/s: $S1 = 3 km = 3000 m$

For the second segment (S2):

• Initial velocity, $V2 = 10 m/s$
• Distance, $S2 = 13 km$

Again, convert the distance from kilometers to meters: $S2 = 13 km = 13000 m$

Now, you can find the total change in distance ($ΔS$) and the total change in time ($Δt$) for the entire journey:

$\Delta S = S1 + S2 = 3000 m + 13000 m = 16000 m$

Next, you need to find the total change in time ($Δt$). To do this, you'll use the formula for time:

$Δt = \frac{ΔS}{V}$

For the first segment (Δt1): $Δt1 = \frac{S1}{V1} = \frac{3000 m}{6 m/s} = 500 seconds$

For the second segment (Δt2): $Δt2 = \frac{S2}{V2} = \frac{13000 m}{10 m/s} = 1300 seconds$

Now, find the total change in time for the entire journey: $Δt = Δt1 + Δt2 = 500 seconds + 1300 seconds = 1800 seconds$

Now, you can calculate the average velocity ($Vср$) for the entire journey:

$Vср = \frac{ΔS}{Δt} = \frac{16000 m}{1800 seconds} = \frac{16000 m}{1800 s} = 8.89 m/s$

So, the average velocity for the entire journey is approximately 8.89 m/s.