Question

Нагретый на солнце камень массой 4,6 кг бросили в воду. Чему равна удельная теплоёмкость камня, если при остывании на 3°C он отдал воде 3,8 кДж тепла? Ответ (округли до сотых): Дж/(кг·°C).

Answer 1

Ответ:

Q = cmt

c = Q/(m*t)

c = 3800/(4,6*3) = 275,36 (округленно)

Ответ: 275,36

Answer 2

Calculation of Specific Heat Capacity

To calculate the specific heat capacity of the stone, we can use the formula:

Q = mcΔT

Where: - Q is the heat transferred (in joules) - m is the mass of the stone (in kilograms) - c is the specific heat capacity of the stone (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we know the following values: - Mass of the stone (m) = 4.6 kg - Change in temperature (ΔT) = -3°C (since the stone is cooling down)

We also know that the stone transferred 3.8 kJ (kilojoules) of heat to the water.

To convert the heat transferred to joules, we multiply by 1000: - Heat transferred (Q) = 3.8 kJ = 3.8 * 1000 J = 3800 J

Now we can rearrange the formula to solve for the specific heat capacity (c):

c = Q / (m * ΔT)

Substituting the known values:

c = 3800 J / (4.6 kg * -3°C)

Calculating the result:

c ≈ -276.6 J/(kg·°C)

Rounding to two decimal places, the specific heat capacity of the stone is approximately -276.6 J/(kg·°C).

Please note that the negative sign indicates that the stone is losing heat as it cools down.