Question

Велосипедист, двигавшийся со скоростью 2 м/с, спускался с горы с ускорением 0,5 м/c^2. Найдите скорость велосипедиста в подножия горы , если спуск продолжался 6 с. ​

Answer 1

Ответ:

решено верно

Объяснение:

v0=2м/с

a=0,5м/с²

t=6с

v=?

v=v0+a×t

v = 2+0,5×6=2+3=5м/с

Answer 2

Ответ:

Объяснение:

V(t) = V₀ + a·t

V(t) = 2 + 0,5·t

V(6) = 2 + 0,5·6 = 5 м/с

Answer 3

Calculation of the Cyclist's Speed

To find the speed of the cyclist at the foot of the mountain, we can use the equations of motion. The cyclist is moving with an initial speed of 2 m/s and experiencing an acceleration of 0.5 m/s^2 while descending the mountain. The descent lasts for 6 seconds.

We can use the equation:

Final velocity = Initial velocity + (Acceleration x Time)

Plugging in the values:

Final velocity = 2 m/s + (0.5 m/s^2 x 6 s)

Calculating the result:

Final velocity = 2 m/s + 3 m/s = 5 m/s

Therefore, the speed of the cyclist at the foot of the mountain is 5 m/s.