Question

Тело массой m=2 кг падает в воздухе с ускорением a=9,3 м/с^2. Определить силу сопротивления воздуха.

Answer 1

Формула:

$m*a=m*g-Fc$

Решение :

$Fc=m*g-m*a=m*(g-a)=2*(9,8-9,3)=1 H$

Ответ: $1H$

Answer 2

Problem Analysis

We are given the mass of an object, m = 2 kg, and the acceleration due to gravity, a = 9.3 m/s^2. We need to determine the force of air resistance acting on the object.

Solution

The force of air resistance can be calculated using the formula:

F = m * a

where F is the force of air resistance, m is the mass of the object, and a is the acceleration due to gravity.

Substituting the given values, we have:

F = 2 kg * 9.3 m/s^2

Calculating the result:

F = 18.6 N

Therefore, the force of air resistance acting on the object is 18.6 N.

Conclusion

The force of air resistance acting on the object with a mass of 2 kg and an acceleration due to gravity of 9.3 m/s^2 is 18.6 N.