Question

Определить силу упругости возникающую при растяжении пружины на 14 см если жесткость пружины равна 550 н/м ​

Answer 1

Дано:                       Решение:

x= 0,14 м                  Fупр = kx  

k= 550 Н/м              Fупр = 550 Н/м * 0,14 м = 77 Н

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Fупр-?                                    Ответ: 77 Н

Answer 2

Calculation of the Spring Force

To determine the force of elasticity that arises when a spring is stretched by 14 cm, we need to use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement or extension of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force exerted by the spring, - k is the spring constant or stiffness of the spring, - x is the displacement or extension of the spring from its equilibrium position.

In this case, we are given that the stiffness or spring constant (k) is equal to 550 N/m, and the displacement or extension (x) is 14 cm.

To calculate the force (F), we need to convert the displacement from centimeters to meters:

x = 14 cm = 0.14 m

Now we can substitute the values into Hooke's Law:

F = (550 N/m) * (0.14 m)

Calculating the result:

F = 77 N

Therefore, the force of elasticity that arises when the spring is stretched by 14 cm is 77 N.