Question

Помогите пожалуйста. Пуля массой 10г вылетает из дула винтовки со скоростью 865 м/с, а через 2 с её скорость стала 300м/с. Найдите изменение импульса пули.

Answer 1

Ответ:

ОТВЕТ

-5,65кг•м/с

Объяснение:

Δp=p2-p1=mv2-mv1=m(v2-v1)=0.01 кг(300-865)=-5,65кг•м/с

ИМПУЛЬС УМЕНЬШИЛСЯ НА 5,65

Answer 2

Calculation of Change in Momentum

To find the change in momentum of the bullet, we can use the formula:

Change in momentum = Final momentum - Initial momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

Given that the mass of the bullet is 10 grams (0.01 kg), the initial velocity is 865 m/s, and the final velocity is 300 m/s, we can calculate the initial and final momenta.

Initial momentum = mass × initial velocity = 0.01 kg × 865 m/s

Final momentum = mass × final velocity = 0.01 kg × 300 m/s

Now we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

Let's calculate it step by step:

Initial momentum = 0.01 kg × 865 m/s = 8.65 kg·m/s

Final momentum = 0.01 kg × 300 m/s = 3 kg·m/s

Change in momentum = 3 kg·m/s - 8.65 kg·m/s = -5.65 kg·m/s

Therefore, the change in momentum of the bullet is -5.65 kg·m/s.