Question

Шарик толкнули с горки, и далее он двигался с ускорением 0.5 м/с^2. через 6 с он достигает основания горки, пребретя скорость 5 м/с. Чему равны начальная скорость и путь, пройденная телом за 6 с, в единицах СИ?

Answer 1

Дано:

a = 0,5 м/с²

a = 0,5 м/с²t = 6 c

a = 0,5 м/с²t = 6 cV = 5 м/с

Найти:

Vо - ?

- ?S - ?

Формула

Vо = V-a×t

S = Vо-t×a/2

Решение:

Vо = 5 м/с - 0,5 м/с² × 6 с = 2 м/с

Vо = 5 м/с - 0,5 м/с² × 6 с = 2 м/сS = 2 м/с - 6 с × 0,5 м/с² / 2 = 21 м

Ответ: начальная скорость Vо = 2 м/с, перемещение S = 21 м..

Answer 2

Problem Analysis

We are given the following information: - The ball is pushed down a slope. - The ball accelerates at a rate of 0.5 m/s^2. - After 6 seconds, the ball reaches the base of the slope with a velocity of 5 m/s.

We need to find: - The initial velocity of the ball. - The distance traveled by the ball in 6 seconds.

Solution

To solve this problem, we can use the equations of motion. The relevant equations are:

1. v = u + at, where: - v is the final velocity, - u is the initial velocity, - a is the acceleration, and - t is the time.

2. s = ut + (1/2)at^2, where: - s is the distance traveled, - u is the initial velocity, - t is the time, and - a is the acceleration.

Let's solve for the initial velocity (u) and the distance traveled (s).

Finding the Initial Velocity (u)

We are given: - Final velocity (v) = 5 m/s - Acceleration (a) = 0.5 m/s^2 - Time (t) = 6 s

Using the equation v = u + at, we can rearrange it to solve for u:

u = v - at

Substituting the given values:

u = 5 m/s - (0.5 m/s^2)(6 s)

Calculating the value:

u = 5 m/s - 3 m/s

u = 2 m/s

Therefore, the initial velocity of the ball is 2 m/s.

Finding the Distance Traveled (s)

We are given: - Initial velocity (u) = 2 m/s - Acceleration (a) = 0.5 m/s^2 - Time (t) = 6 s

Using the equation s = ut + (1/2)at^2, we can substitute the given values to find the distance traveled:

s = (2 m/s)(6 s) + (1/2)(0.5 m/s^2)(6 s)^2

Calculating the value:

s = 12 m + (1/2)(0.5 m/s^2)(36 s^2)

s = 12 m + (0.25 m/s^2)(36 s^2)

s = 12 m + 9 m

s = 21 m

Therefore, the distance traveled by the ball in 6 seconds is 21 meters.

Summary

In summary, the initial velocity of the ball is 2 m/s, and the distance traveled by the ball in 6 seconds is 21 meters.

Please let me know if you need any further clarification.