Question

Прямой проводник длиной J = 0, 2 м помещён в однородное магнитное поле с индукцией B = 0, 5 Tл. При пропускании по этому проводнику электрического тока силой I = 2A на проводник начинает действовать сила F = 0, 1 Hсо стороны поля. Найди острый угол а, образуемый проводником с линиями индукции магнитного поля. ответ вырази в градусах и округли до целого значения.

Answer 1

Ответ:

30

Объяснение:

Из формулы F=B*L*I*sina

sina=1/2, значит угол a равен 30

Answer 2

Calculation of the Angle Formed by the Conductor and Magnetic Field Lines

To find the angle formed by the conductor and the magnetic field lines, we can use the formula:

F = BILsin(a)

Where: - F is the force acting on the conductor (given as 0.1 N) - B is the magnetic field strength (given as 0.5 T) - I is the current flowing through the conductor (given as 2 A) - L is the length of the conductor (given as 2 m) - a is the angle between the conductor and the magnetic field lines (to be determined)

We can rearrange the formula to solve for the angle a:

sin(a) = F / (BIL)

Let's substitute the given values into the formula and solve for the angle a.

sin(a) = 0.1 N / (0.5 T * 2 A * 2 m)

sin(a) = 0.1 N / (2 T * 2 A * 2 m)

sin(a) = 0.1 N / (8 T*A*m)

sin(a) = 0.0125

To find the angle a, we need to take the inverse sine (arcsin) of 0.0125.

a = arcsin(0.0125)

Using a calculator, we find that the angle a is approximately 0.72 degrees.

Therefore, the acute angle formed by the conductor and the magnetic field lines is approximately 0.72 degrees.