Question

Ар­ка­дий налил в ка­стрю­лю воду мас­сой 4 кг и начал её на­гре­вать. На сколь­ко гра­ду­сов он смог на­греть воду, если она по­лу­чи­ла ко­ли­че­ство теп­ло­ты, рав­ное 252 000 Дж? Удель­ная теплоёмкость воды 4200 Дж/(кг · °C), по­те­ря­ми теп­ло­ты можно пре­не­бречь. Ответ дайте в °C.

Answer 1

Дано:                                   Решение:

m = 4 кг                              Q = cmt ⇒ t=Q/mc

Q =  252000 Дж                t = 252000 Дж / (4200Дж/(кг*°С) * 4 кг) = 15 °С

c = 4200 Дж/(кг*°С)

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t-?                                              Ответ: 15 °С

Answer 2

Calculation of the Temperature Increase

To calculate the temperature increase of the water, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat transferred to the water (in joules) - m is the mass of the water (in kilograms) - c is the specific heat capacity of water (in joules per kilogram per degree Celsius) - ΔT is the change in temperature of the water (in degrees Celsius)

In this case, the mass of the water is given as 4 kg, and the amount of heat transferred to the water is given as 252,000 J. The specific heat capacity of water is 4200 J/(kg·°C).

Let's calculate the change in temperature:

252,000 J = (4 kg) * (4200 J/(kg·°C)) * ΔT

Simplifying the equation:

ΔT = 252,000 J / (4 kg * 4200 J/(kg·°C))

Calculating the result:

ΔT = 15°C

Therefore, Arkadiy was able to heat the water by 15 degrees Celsius.