Question

Прикладывая силу 250 Н, груз массой 30 кг равномерно подняли по наклонной плоскости. Длина наклонной плоскости равна 20 м, высота – 5 м. Чему равен КПД наклонной плоскости? Прими g=10 Н/м. Ответ вырази в процентах.СРОЧНО 50 БАЛЛОВ

Answer 1

Дано:

F=250Н; m=30кг

l=20м; h=5м

g=10 Н/м

_________

КПД-?

Решение:

КПД=(Аполез/Аполная)*100%

Аполез=mgh=30*10*5= 1500 Дж

Аполн=Fl=250*20=5000 Дж

КПД=(1 500 Дж/5000 Дж)*100%=30%

Answer 2

Calculation of Efficiency (КПД) of the Inclined Plane

To calculate the efficiency (КПД) of the inclined plane, we need to determine the work input and work output.

The work input is the force applied to lift the load up the inclined plane, and the work output is the force required to lift the load vertically.

Given: - Force applied (F) = 250 N - Mass of the load (m) = 30 kg - Length of the inclined plane (L) = 20 m - Height of the inclined plane (h) = 5 m - Acceleration due to gravity (g) = 10 N/m

To calculate the work input, we use the formula: Work input = Force applied × distance Work input = F × L

Substituting the given values: Work input = 250 N × 20 m

To calculate the work output, we use the formula: Work output = Force required to lift the load vertically × distance Work output = Weight of the load × height Work output = m × g × h

Substituting the given values: Work output = 30 kg × 10 N/kg × 5 m

Now, we can calculate the efficiency (КПД) using the formula: Efficiency (КПД) = (Work output / Work input) × 100

Substituting the calculated values: Efficiency (КПД) = (Work output / Work input) × 100 Efficiency (КПД) = [(30 kg × 10 N/kg × 5 m) / (250 N × 20 m)] × 100

Simplifying the expression: Efficiency (КПД) = (1500 N·m / 5000 N·m) × 100 Efficiency (КПД) = 30%

Therefore, the efficiency (КПД) of the inclined plane is 30%.

Please note that the calculation assumes ideal conditions and does not take into account factors such as friction or other losses.