Question

Помогите пожалуйста..... Вдоль упругого шнура распространяется поперечная волна со скоростью 20 м/с, период колебаний точек шнура 50 мс. Определите частоту и длину волны.​

Answer 1

Ответ:

......................................

Answer 2

Ответ:

Объяснение:

Дано:

V = 20 м/с

T = 50 мс = 0,050 с

_____________

λ - ?

Длина волны:

λ = V·T

λ = 20·0,050 = 1 м

Частота:

ν = 1 / T = 1 / 0,050 = 20 Гц

Answer 3

Calculation of Frequency and Wavelength

To determine the frequency and wavelength of a transverse wave propagating along an elastic string, we can use the given information:

- Speed of the wave: 20 m/s - Period of oscillation: 50 ms

The frequency (f) of a wave is the reciprocal of its period (T), so we can calculate the frequency using the formula:

f = 1 / T

Substituting the given period into the formula:

f = 1 / 0.05 s = 20 Hz

The wavelength (λ) of a wave can be calculated using the formula:

v = f * λ

where v is the velocity of the wave. In this case, the velocity is given as 20 m/s. Rearranging the formula, we get:

λ = v / f

Substituting the given values into the formula:

λ = 20 m/s / 20 Hz = 1 m

Therefore, the frequency of the wave is 20 Hz, and the wavelength is 1 meter.

Please let me know if there is anything else I can help you with!