Question

электрон влетает в однородное магнитное поле индукция которого 0.6 тл, со скоростью 16000 км/с перпендикулярно линиям индукции. определить силу с которой магнитное поле действует на электрон​

Answer 1

Ответ:

Объяснение:

Дано:

q = 1,6·10⁻¹⁹ Кл  - модуль заряда электрона

B = 0,6 Тл

V = 16 000 км/с = 16·10⁶ м/с

______________

F - ?

Сила, действующая на электрон в магнитном поле:

F = q·B·V

F = 1,6·10⁻¹⁹·0,6·16·10⁶ ≈ 1,5·10⁻¹² H

Answer 2

Introduction

When an electron enters a uniform magnetic field, it experiences a force due to the interaction between the magnetic field and the moving charge. In this case, the electron is entering a magnetic field with an induction of 0.6 T and a velocity of 16000 km/s perpendicular to the lines of induction. We need to determine the force with which the magnetic field acts on the electron.

Calculation

The force experienced by a charged particle moving in a magnetic field can be calculated using the formula:

F = q * v * B * sin(θ)

Where: - F is the force experienced by the charged particle - q is the charge of the particle - v is the velocity of the particle - B is the magnetic field induction - θ is the angle between the velocity vector and the magnetic field vector

In this case, the electron has a charge of -1.6 x 10^-19 C (coulombs), a velocity of 16000 km/s, and the magnetic field induction is 0.6 T. The angle between the velocity vector and the magnetic field vector is 90 degrees since the electron's velocity is perpendicular to the lines of induction.

Plugging in the values into the formula, we get:

F = (-1.6 x 10^-19 C) * (16000 km/s) * (0.6 T) * sin(90°)

Since sin(90°) = 1, the equation simplifies to:

F = (-1.6 x 10^-19 C) * (16000 km/s) * (0.6 T)

Now, let's calculate the force:

F = (-1.6 x 10^-19 C) * (16000 km/s) * (0.6 T) = -1.536 x 10^-11 N

Therefore, the force with which the magnetic field acts on the electron is approximately -1.536 x 10^-11 N.

Conclusion

The force experienced by the electron when it enters a uniform magnetic field with an induction of 0.6 T and a velocity of 16000 km/s perpendicular to the lines of induction is approximately -1.536 x 10^-11 N.