Question

9) З одної й тої ж самої точки падають два тіла. Друге тіло розпочало падати на с пізніше першого. Визначити відстань між тілами через 10c після падіння першого тіла і знайти, в скільки разів швидкість першого тіла більше швидкості другого в цей же момент часу.​

Answer 1

Ответ: 405 м       ≈ 1,11

Объяснение:

Answer 2

Problem Statement

Two bodies are falling from the same point. The second body starts falling later than the first. We need to determine the distance between the bodies 10 seconds after the first body starts falling. Additionally, we need to find the ratio of the velocity of the first body to the velocity of the second body at that moment.

Solution

To solve this problem, we need to consider the motion of the two bodies separately.

Let's assume that the first body starts falling at time t = 0 seconds, and the second body starts falling at time t = t1 seconds.

1. Distance between the bodies after 10 seconds: - The distance traveled by the first body after 10 seconds can be calculated using the formula: distance = (1/2) * g * t^2, where g is the acceleration due to gravity (approximately 9.8 m/s^2) and t is the time in seconds. - Therefore, the distance traveled by the first body after 10 seconds is: distance1 = (1/2) * 9.8 * (10^2).

- The distance traveled by the second body after 10 seconds can be calculated in a similar way, but we need to consider that it starts falling later. Therefore, the time for the second body will be t = 10 - t1 seconds. - Therefore, the distance traveled by the second body after 10 seconds is: distance2 = (1/2) * 9.8 * ((10 - t1)^2).

- The distance between the bodies after 10 seconds is the difference between the distances traveled by the first and second bodies: distance_between_bodies = distance1 - distance2.

2. Ratio of velocities at that moment: - The velocity of an object in free fall can be calculated using the formula: velocity = g * t, where g is the acceleration due to gravity and t is the time in seconds. - Therefore, the velocity of the first body after 10 seconds is: velocity1 = 9.8 * 10.

- The velocity of the second body after 10 seconds can be calculated in a similar way, but we need to consider that it starts falling later. Therefore, the time for the second body will be t = 10 - t1 seconds. - Therefore, the velocity of the second body after 10 seconds is: velocity2 = 9.8 * (10 - t1).

- The ratio of velocities at that moment is the ratio of the velocities of the first and second bodies: velocity_ratio = velocity1 / velocity2.

Therefore, the distance between the bodies after 10 seconds is distance_between_bodies = (1/2) * 9.8 * (10^2) - (1/2) * 9.8 * ((10 - t1)^2), and the ratio of velocities at that moment is velocity_ratio = (9.8 * 10) / (9.8 * (10 - t1)).

Please note that we need to know the value of t1 to calculate the exact values of the distance and velocity ratio.