Question

Через провідник, опір якого дорівнює 16 Ом, за 8,8 хв проходить заряд 42 Кл. Знайди напругу, прикладену до кінців провідника.   Відповідь заокругли до десятих ​

Answer 1

Ответ:

Объяснение:

Дано:

R = 16 Ом

t = 8,8 мин = 528 c

q = 42 Кл

_____________

U - ?

Сила тока:

I = q / t = 42 / 528 ≈ 0,08 А

Напряжение:

U = I·R = 0,08·16 ≈ 1,3 В

Answer 2

To find the voltage applied to the ends of the conductor, we can use Ohm's Law, which states that the voltage (V) is equal to the product of the current (I) and the resistance (R). In this case, the resistance of the conductor is given as 16 Ohms.

We are given the charge (Q) that passes through the conductor in a certain time interval. The charge is given as 42 Coulombs, and the time interval is given as 8.8 minutes. However, we need to convert the time to seconds for consistency in the units.

Let's calculate the current first. The current (I) is equal to the charge (Q) divided by the time (t): I = Q / t

Converting the time to seconds: t = 8.8 minutes * 60 seconds/minute = 528 seconds

Substituting the given values: I = 42 Coulombs / 528 seconds

Now, we can calculate the voltage (V) using Ohm's Law: V = I * R

Substituting the given resistance: V = (42 Coulombs / 528 seconds) * 16 Ohms

Calculating the voltage: V = 1.27272727... Volts

Rounding the answer to the nearest tenth: V ≈ 1.3 Volts

Therefore, the voltage applied to the ends of the conductor is approximately 1.3 Volts.