Question

50 Б!!!!!ПОМОГИТЕ ПЖЛ!!!!Найдите заряд шарика массой 41 мг, находящегося в равновесии под действием гравитационной и электростатической силы в поле напряжённостью 400 кВ/м.

Answer 1

Ответ:

10,25*10^(-10)Кл

Объяснение:

Раз в равновесии значит

Fкл=mg

qE=mg

q=mg/E

q=41*10^(-6)*10/(4*10^5)=10,25*10^(-10)Кл

Answer 2

Finding the Charge of a Ball in Equilibrium

To find the charge of a ball in equilibrium under the influence of both gravitational and electrostatic forces in a field with an electric field strength of 400 kV/m, we can use the following formula:

Fg = Fe

Where: - Fg is the gravitational force acting on the ball - Fe is the electrostatic force acting on the ball

The gravitational force can be calculated using the formula:

Fg = m * g

Where: - m is the mass of the ball - g is the acceleration due to gravity (approximately 9.8 m/s^2)

The electrostatic force can be calculated using the formula:

Fe = q * E

Where: - q is the charge of the ball - E is the electric field strength

Since the ball is in equilibrium, the gravitational force and the electrostatic force are equal. Therefore, we can set up the following equation:

m * g = q * E

Now, let's substitute the given values into the equation:

- Mass of the ball (m) = 41 mg = 41 * 10^-6 kg - Acceleration due to gravity (g) = 9.8 m/s^2 - Electric field strength (E) = 400 kV/m = 400 * 10^3 V/m

Substituting these values into the equation, we get:

(41 * 10^-6 kg) * (9.8 m/s^2) = q * (400 * 10^3 V/m)

Simplifying the equation, we find:

q = (41 * 10^-6 kg * 9.8 m/s^2) / (400 * 10^3 V/m)

Evaluating this expression, we can find the charge of the ball in equilibrium.

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