Question

Скласти рівняння прямої,яка проходить через точку А(2;-3) і точку перетину прямих 2х-y-5=0 і x+y-1=0

Answer 1

I can help you with your math problem. To find the equation of the line that passes through the point A(2;-3) and the intersection point of the lines 2x-y-5=0 and x+y-1=0, we need to do the following steps:

- First, we need to find the coordinates of the intersection point of the two given lines. To do this, we can solve the system of equations by elimination or substitution. For example, by adding the two equations, we get 3x-6=0, which implies x=2. Then, by substituting x=2 into either equation, we get y=-1. Therefore, the intersection point is B(2;-1). - Next, we need to find the slope of the line that passes through A and B. To do this, we can use the formula m=(y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are any two points on the line. In this case, we can use A(2;-3) and B(2;-1) as the two points. Plugging in the values, we get m=(-1-(-3))/(2-2)=2/0. This means that the slope is undefined, and the line is vertical. - Finally, we need to find the equation of the vertical line that passes through A and B. To do this, we can use the fact that all points on a vertical line have the same x-coordinate. In this case, the x-coordinate is 2, so the equation of the line is x=2.Ответь+подробно.++Скласти+рівняння+прямої,яка+проходить+через+точку+А(2;-3)+і+точку+перетину+прямих+2х-y-5=0+і+x+y-1=0+