Question

2 Реши задачу.от двух лодочных станций, расстояние между которымneer 54 км, отправились одновременно в одном наплодка и катер. Скорость катера - 25 км/ч, а лодкиЧерез некоторое время катер догнал лодку. Найди рапройденное катером.и в 25 км/чS? KM54 кмV, в 7 км/ч написона на тетрадь​

Answer 1

Ответ:

1) 25-7=18 (км/ч) - скорость отставания.

2) 54:18=3 (ч) - время.

3) 25•3=75 (км) - расстояние катера.

В: 54:(25-7)•25=75 (км).

Ответ: расстояние катера-75 км.

Пошаговое объяснение:

Answer 2

Problem Analysis

To solve this problem, we need to find the distance covered by the motorboat (катер) when it catches up with the rowboat (лодка). We are given the speed of the motorboat, the speed of the rowboat, and the distance between the two boat stations.

Calculating the Distance Covered by the Motorboat

First, we can calculate the time it takes for the motorboat to catch up with the rowboat using the formula: \[ \text{time} = \frac{\text{distance}}{\text{relative speed}} \]

The relative speed is the difference between the speeds of the motorboat and the rowboat.

Solution

Given: - Distance between the boat stations, \(d = 54 \, \text{km}\) - Speed of the motorboat, \(v_m = 25 \, \text{km/h}\) - Speed of the rowboat, \(v_r = 7 \, \text{km/h}\)

The relative speed is: \[ v_{\text{relative}} = v_m - v_r = 25 \, \text{km/h} - 7 \, \text{km/h} = 18 \, \text{km/h} \]

The time taken for the motorboat to catch up with the rowboat is: \[ t = \frac{d}{v_{\text{relative}}} = \frac{54 \, \text{km}}{18 \, \text{km/h}} = 3 \, \text{hours} \]

The distance covered by the motorboat when it catches up with the rowboat is: \[ \text{distance} = v_m \times t = 25 \, \text{km/h} \times 3 \, \text{hours} = 75 \, \text{km} \]

Answer

The motorboat covers a distance of 75 km when it catches up with the rowboat.

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